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122 CHAPTER 9 1960 Guide Table t2A.... Coefficients of Transmission (U) of Concrete Roor-Ceifing Constructions1 (Winter Conditions, Upward How) feat* or* *xpr*cf*d in Bfu p*r (hood (square foot Ifabrwrfwrl degr* dffitnsac* tn t*ap*fofur between the air on fh* fwt> trd<), and ore bated on tfifj air (no wind) eonditioei on badi ctdet Exempt*--Boer J 4 ExotspJ* of Substitution 2 3 4 S47A Re&ittanccM used are given below in this table or in Table S or 4 Heated room below unheated space Construction (hhai flow up) Resistance (A) 1. Top surface (still air)................. ................... 0.61 2. Asphalt tile and felt.......................................... 0.11 3. Plywood G in.)................................................. 0.73 4. Air space*............................................................. o.8S 5. Concrete slab 4 in. (av. A)............... ............0.40 6. Air space* (8 in.)................................................ 0.8S 7. Meta) lath and % plas. (sand agg.)...............0.23 8. Bottom surface (still air)....................................0.61 Total resistance.................... ............................ 4.SI U - 1/A - 1/4.34 -......................................... 0.23 See value 0.23 in bold face type in table below. Assistances used are given below in this table or in Table S or 4 Replace items 2, 3, and 4 with bard wood block (* in.) on slab Total resistance........................................... 4-94 Deduct 2. Asphalt tile and felt................ 0.11 3. Plywood in.)...................... 0.76 4. Airspace....................................0.66 1.74 Difference................................... Add 2. Wood block (l9f6 in-).. S.60 0.74 Total resistance.... V - 1/A - 1/3.34 3.54 0.30 To Adfud U Vohet for Coaxtmdioo with Added Inadalion la Air Spec* above Stnpended Camg, Sm Table Id Tjrp* of Rnie Roor CeSng Applied Dvedty to Slob ILL (Sand kit'. 030*1 Hi". fyp* of Ceding Suspended Offing Gypsum bd. Meta) letti (H hi ond Hm. and plot Acoustical <3* On furring On gyp* [Uwt. (Sand la OggJ oggj 003*1 or tun bd. dKMWb IH a) M " KM K &* 0.08 0.02 A*. 0.32 0*04 0.4) 0.47 1.51 2.10 Number 0.62 0.59 Floor tile* or linoleum (H u0.................... 0.03 0.60 0.57 0.35 0.29 0.32 0-35 0.34 0.32 0.34 0. 0.25 0.22 0.25 0.22 Concrete4 (sand agg.) (4 in.) 0.33 (6 in.) O.48 Wood block (lKe in.) on slab............................ 0.74 0.42 0.41 0 Floor on sleepers Plywood subfloor ($$ in.), felt and floor tile* or linoleum (K )............................. 0.30 0.22 9.19 0.22 O.J 0.27 0.21 0-19 Wood subfloor (*4# in.), felt and hard* wood (K in.)._ ____ 0.24 0.24 0.18 0.18 0.52 0.50 0. oiii Floor tile* or linoleum G$ in.)...................... 0.05 0.50 0.48 0.50 0-31 0.28 0.32 0.29 0.31 0.30 0.34 0.25 0.22 0.23 0.20 Concrete4 (sand egg) (8 tn.) 0.340.72 (10 in.) C Wood block (1Ko in.) on slab............................ 0.74 0.37 0.36 Floor on sleepers Plywood subfloor G6 in.), felt and floor tile* or linoleum (j in.)............................. 0. 0.25 0.2S 0.17 0.160.17 0.15 Wood subfloor (*M* in.), felt and nardwood (K in.)............/.7210.22 0.221 0.22*0.184). 16H). 18 0.17 0.17 * Sm text wirtioB fielmlitfnt Orcill CMfidobforb^i of * Toedjort V mine* tor theeffectof added insnlxlkra bniwca framing nwmhnm, TM. jj. *TU4* U cube taed only if sleeperepeoeb ooa^etiectr**. Tbe sleeper *ir tpsee it not to bo counted in naiwg Table U. * Concrete h amumed to bar*a thermal coftdaetMity k of U.0as given in Table 4. * Includes asphalt, robber, and plastic til* Q4 in.), eentsie UM on tarxaao (1 in.). o.ielo. 14I0.15*0.13 Heat',Transmission Coefficients of Building Materials 123 Table 12B.... Coefficients of Transmission (Lf) of Concrete Boor-Ceiling Constructions* (Summer Conditions, Downward How) Co*deals or* expmted in Bfu per (boor) (square foot) (fahncM degree difference to temperature between ffa* air on fh* two tided, end ar* baand on diZf air (no wtndl condttfons oa bolh tide* TYPE OF CHUNG Coiling Applied Directly to Slab Suspended CelCng Gypsum bd. Metol (mb (M inj and Plea. and ptas. Acoustical til* Type of Oodc fjrp* of faidi Floor (U.wt [Sand 000*1 000*1 K'<n- M*. (Sand (Sand >09-1 H*- O0Q-) Ka ogg.) H 009-1 H*- bd*G$ W Concrete4 (sand egg.) (4 in.) (6 in.) 0.33 0.48 Concrete4 (sand Agg) (8 in.) 0.64 (10 iD.) 0.80 T1 u 9.45 0.44)0.29 0.26 0.25) 0.28)0.2110.19(0.20 0.18 Floor tile* or linoleum (K in-)...................... 0.44 0.25 0 0.27 0.18 Wood block (lKe in.) 00 slab............................ 0.34 0.22 0.21 0.23 0.16 Floor on sleepers Plywood subfloor 4K 10.), felt and floor tile* or linoleum Ojj )........................... 0.23 0.17 0.13 Wood subfloor <aKi in.), felt and hard wood ( in.).......... 0.20 0.19 0-20 0.14 0.15 015 0.16 0.13 0.12 0.13 0.12 0 0.39 0.24 0.23 0.20 0.19 0.17 Floor tile* or linoleum (Min-)...................... 0.37 0. 230 .24 24 0.23 0.20 0.19 0.17 Wood block (lHe iu-) on slab............................ 0.30 0.30 0.21 0.20 0.17 0.15 Floorod sleepers Plywood subfloor (34 in.), felt and floor tile* or linoleum 0 in.)........................... Wood subfloor (8Ma in.), felt and hard wood P in.)........... 1.78 0.19 0.18 0.18 0-15 0.14 9.14 0.14 0.14 * 8e* text section Overall Coefficient* for baab of mleulatioas. b To adjust 0 vetoes for the effect of added insulation between framing members, see Table IS. * Table 14 ten b* used only if atoeper space bnonretieetive. The sleeper air space boot to be coasted in (nine Table IS. 4 Concrete is mvtrimrri to bar* a therms) conductivity k of 1X0 u given in Table 4. * Include* asphalt, robber, and plastic tile (H In-), ceramic tile on terzasso (1 in,). leaving equal air spaces on the two sides. The coefficient /< is desired for two cases in which (a) the blanket has non-reflective surfaces on both sides, so that both air spaces are non-reflective (E -- 0-82) and, (5) the blanket has one highly reflective surface, so that one of the air spaces is highly reflective (E - 0.05). Solution: (a) In Table 16, Part A, when V without added insulation is 0-24, Oi for one inch of fibrous insulation and one non-refleetive air space, is 0.127 in Column 3. To add the second nonreflective air space, enter Column 6 at 0.127, and by interpo lating find U< ** 0.112 in Column 9. Use 0.11. (5) Ui for one inch of fibrous insulation and one noo-reflective air space is 0.127 as in (a)i To add one E = 0.05 air space, enter Column 8 at 0.127 and by interpolating find Vi = 0.092 in Column 11. Use 0.09. (Cntimcrf en f- 131)