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CHAPTER 50
1946 Guide
STORAGE CAPACITY AND HEATING LOAD
In estimating the size of hot water storage tank required and the heating capacity to be provided either from the boiler or from an inde pendent domestic hot water heater, it is necessary to know the total quantity of water to be heated per day, and the maximum amount which will be used in any one hour, as well as the duration of the peak load.
In cases where the requirements for hot water are reasonably uniform, as in residences, apartment buildings, hotels, and the like, smaller storage capacity is required than in the case of factories, schools, office buildings, etc., where practically the entire day's usage of hot water occurs during a very short period. Correspondingly, the heating capacity must be pro portionately greater with uniform usage of hot water than with inter mittent usage where there may be several hours between peak demands during which the water in the storage tank can be brought up to tempera-
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Fig. 1. Methods of Arranging Hot Water Circulation Lines
ture. As a general rule it is desirable to have a large storage capacity in order that the heating capacity and consequently the size of the heater, or the load on the heating boiler, may be as small as possible.
In estimating the hot water which can be diawn from a storage tank it should be borne in mind that only about 75 per cent of the volume of the tank is available, as by the time this quantity has been drawn off the incoming cold water has. cooled the remainder down to a point where it can no longer be considered hot water.
Where steam from the heating boiler is used to heat domestic hot water, the computed load on the boiler should be increased by 4 sq ft EDR (equivalent direct radiation) for every gallon of?water per hour heated through, a 100 F rise'. The actual requirement is-1-0--0-2xio8 --33 = ^-48 sq ft
per gallon of water heated 100 F. The value of 4 allows for transmission losses, etc.
There are two ways in common use of estimating the hot water require ments of a building; first, by the number of people and second, by the number of plumbing fixtures installed. Where the number of people to
Hot Water Supply
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be served is known or can be reasonably estimated, the data in Table 1 may be used.
Examine 1. From Table 1, a residence housing five people would have a daily requirement of 5 X 40 = 200 gal per day, and a maximum hourly demand of 200 X M
= 28:5 gal. The heater should have a storage capacity of 200 X X = 40 gal and a
heating capacity of 200 XM = 28-5 gal per hour.
The conditions given in Example 1 may be cited as average. It is possible to vary the storage and heating capacity by increasing and decreasing one over the other. Such a condition is illustrated in Ex ample 2.
Example 2. Assume an apartment house housing 200 people. From the data in Table 1: Daily requirements -- 200 X 40 = 8000 gal. Maximum hours demand =
Table 1. Estimated Hot Water Demand per Person for Various Types of Buildings
Type of Building
Residences apts., hotels, etc.
Office buildings
Factory buildings
Restaurants $0.50 meals $1.00 meals $1.50 meals
-
Restaurants 3 meals per day
Restaurants 1 meal per day
Hot Water Required
at X40 F
Max. Hourly Demand in
Relation to Day's Use
Duration of Peak
Load Hours
Storage Capacity in Relation to
Day's Use
Heating Capacity in . Relation to
Day's Use
40 gal per person per day
'X
4
X
X
2 gall per person per day
X
2
X
X
5 gal per person per day
X
I -X
X
1.5 gal per meal 2.5 gal per meal 4.5 gal per meal
Ho Xo
Ko 8
X
Mo
X2X
X
8000 XH = 1140 gal. Duration of peak load = 4 hours. Water required for 4-hour peak = 4 X 1140 = 4560.
If a 1000 gal storage tank is used, hot water available from the tank = 1000 X 0.75 = 750. Water to be heated in 4 hours = 4560 -- 750 = 3710 gal. Heating capacity per
hour =
= 930 gal.
If instead of a 1000 gal tank, a 2500 gal tank had been installed, the required heating
_ L 4560 - (2500 X 0.75)
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capacity per hour would be----------- ------:------------ = 671 gal.
Table 2 may be used to determine the size of water heating equipment from the number of fixtures. To obtain the probable maximum demand multiply the total quantity, for the fixtures by the Demand Factor in
line 11.. The heater or coil should have a water heating capacity equal to this probable maximum demand. The storage tank' should have a capacity equal to the probable maximum demand multiplied by the storage capacity factor in line 12. Example 3 will illustrate the procedure.