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e R e g iste r d e liv e ry vo lu m e s in c o lu m n 1 ore fo r soro le n g th o f d u o t.
g ro u p ).
each
in
v a lu e
; rJ^egister^Delivery Volume in CFM' per 1000 B T U per H r.
....... (For Buildings 'Having aH eat LossGreater than SSO^OOO-BTU/Hr.) .......
T b 'm p b b a t u r e , R e g is t e r T e m p e r a t u r e a n d R e g is t e r . D e l iv e r y (CFM)
378
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CHAPTER 20
1955 Guide
Forced Warm Air Systems
Table 5. Determination of Free Area and Total Pressure Loss of Register
for 22 Deg Deflection .of Aik .h'c'd. -
'
Register Free Area in Square Inches (Upper value in each group)
Pr1/T TSiftQ ttl Tn/'koo nf Vtfntar l T />
___I
\
CpM Up to 59
Residential Use
Reg. Size Pbeb-
OB BUBE Equiv Lose
alent
10 x 4 10 x 6
.01 ,01
60-69
10 x 6 12 x 4
.01 .02
70-99
10 x 6 12x6
.02 : ,02
Residential Use
Cfm 100-119
Reg. . Size
OB Equiv
alent
12x6 14x4
PRESSDBS Loss
.02 .02
120-129
12 x 6 14x6
.02 .02
130-169 14 x 6
;o2
CPM
700-739 740-779 780-819
Distance Fbom Regibtbb to _________Opposite Wall -
i 35-35 40-49 60-69 60-69 70-79
A ]l 243 186 I 127 85 0.02 0.031 0.06 0.11 271 208 141 94 0.02 0.03 0.05 0.10
170-189 14x8.
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R e g is te r te m p e ra tu re , F a h re n h e it. R e g is te r d o liv o ry v o lu m o in e u b io
i A:
.Se l e c t io n o f
T able i.
- )! /
jf
AB
A' 'B''
I08?, it is pertoi^i
^>5^ n distance ^rom register to opposite wall is unsatisfactory on account of size or pressure
9uiremeat8 fall in
one or more spaces left or ngnt in the tables to obtain a more suitable register. If re-
b Total n
lank 8pace' se^ect two registers m place of one and divide CFM capacity between the two registers,
include stacked (atftt* pluf> velocit'y) loss * based on FLAT FACE ADJUSTABLE BAR TYPE and dots NOT
^ halls. a
4 VaJu ,
^ne ^ and -A' should not be used in applications such as churches, auditoriums, and eon--
ter8, cUrtiWina8andfschoobftI1<* shoul<I not ** 086(1 applications such as residential wo rk, motion picture thea-
Por floor and baseboard registers where a velocity of approximately 300 FPM ia used, the free area = fojj. X 144
Approximately, 5TM Assume a pressure loss of 0.01.
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