Document 7OdJROR222NO9y2GMnz06Dmw8
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HEATING VENTILATING AIR CONDITIONING GUIDE 1942
This statement lacks thermodynamic soundness due to actual departures from Dalton's Law, but has real practical merit as an approximation.
Example S. Calculate the humidity ratio of saturated moist air at 68 F, 30 in. Hg.
Solution. The saturation pressure of pure water at 68 F from Table 6 is 0.68980 in. Hg; hence,
0.62193 X 0.68980 M's = -------- 29 3102--------- =
, , .. .. (pound per pound of dry air).
It is also frequently stated that moist air is saturated when the space (volume) occupied by it contains the maximum weight of water vapor at the given temperature. This means that any additional water would have to be in the liquid or solid phase. But under proper circumstances the water vapor can be supersaturated, in which case the space occupied by the. mixture can contain more than the maximum possible water vapor. The statement is therefore meaningless as a definition of saturation.
A precise definition must necessarily refer to the co-existence of at least two distinct phases, say, liquid and vapor. These can only co-exist in stable equilibrium if evaporation of the liquid or condensation of the vapor under conditions of constant total volume and constant total internal energy would have to involve a decrease of total entropy. This would be the situation if, and only if, the pressure, the temperature, and each component chemical potential has the same value in each phase.
In the case of moist air, the general conditions for saturation previously stated can be deduced from Equation 9 together with available data on the solubility of air in the liquid. They can be reduced to the form,
where
Ws = 0.62193 -------- P ~ P.
i.PF) (DF) Pm (RE) Ps
(13a) (13b)
The liquid (or solid) phase will contain a small amount of dissolved air and the Raoult factor (RF) expresses the effect of this dissolved air in lowering the vapor pressure in accordance with Raoult's Law. The Poynting factor (PR) accounts for the fact that the very presence of dry air requires the liquid (or solid) to support a higher pressure at saturation than it would if no dry air were present. The Dalton factor (DF) expresses the effect of intermolecular forces in the vapor phase. All three factors depend more or less on pressure as well as on temperature.
The Raoult and Poynting factors are calculable. The order of magni tude of the Dalton factor can now be determined by computing its value at one temperature and pressure using the information previously referred to, namely, 2Aaw = 0.075 (Aaa + 4,,). At 68 F, 29.921 in.
Hg, for example,
1.00073 X 1.0052
p`
1.00002
p8
This indicates departures from Dalton's Law of the order of 0.5 per cent. The data in Table 6 which are based on an assumed value of unity for the
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CHAPTER 1. THERMODYNAMICS OF AIR AND WATER MIXTURES
Dalton factor have not been revised pending final results on the measure ment of the interaction constant [10].
Relative Humidity
The ratio of actual humidity ratio W to the saturation humidity ratio Ws corresponding to the actual temperature and the observed pressure is denoted by the symbol p. and may be called alternatively degree of satura tion or percent saturation; thus,
W = p Ws
(14)
Example 4. Air is to be maintained at 70 F, 40 per cent saturation when outside air is at 0 F, 70 per cent. The observed pressure may be taken to be 29.921 in. Hg. Find the weight of water to be added to each pound of dry air using Table 6.
Solution. The desired humidity ratio is 0.40 X 0.01574 = 0.006296 while that of outside air is 0.70 X 0.0007852 = 0.000550. Hence the weight of water to be added is 0.006296 -- 0.000550 = 0.005746 lb per pound dry air.
Under Dalton's Law the water vapor exerts a partial pressure pw which may be calculated from the given humidity ratio W and the observed pressure P by means of Equation 11. The ratio of this partial pressure pw to the saturation pressure of pure water pe corresponding to the actual temperature is called relative humidity and may be denoted by the symbol
thus,
*> = Pa
(15)
The relation between p and $ is obtained directly from Equations 11 and 12 and is
> - (frg)
>
whence it is clear that for ordinary temperatures where ps and therefore pv are small compared with P, the two are approximately equal.
As an aid in quickly translating degree of saturation p into relative
humidity <F, the following empirical equation may be substituted for
Equation 15a:
<J> = p + a p (1 -- p)
(15b)
where a depends upon temperature for standard atmospheric pressure, as
s}
shown by the values in Table 7. Within the limits of accuracy of (15b) this may also be written
p = <t> -- a <&(l -- 4>)
(15c)
and used to translate relative humidity into degree of saturation p.
Table 7. Percentage Differences Corresponding to Temperature for Equation 15b________________________________________
Temp f
t
5 10 15 20 25
Per Cent
a
0.16 0.21 0.27 0.34 0.44
Temp f
t
30 35 40 45 50
Per Cent
a
0.55 0.68 0.83 1.01 1.22
Temp f
/
55 60 65 70 75 .
Per Cent
a
1.47 1.76 2.10 2.50 2.97
Temp f
t
80 85 90 : 95 100
Per Cent
a
3.51 4.14 4.86 5.70 . 6.67,
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